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D( x )
x < 0
x < 0
x in <0:+oo)
x^3+x^(1/2) = 0
t_1 = x^(1/2)
1*t_1^6+1*t_1^1 = 0
t_1^6+t_1 = 0
t_1*(t_1^5+1) = 0
1*t_1^5 = -1 // : 1
t_1^5 = -1
t_1^5 = -1 // ^ 1/5
t_1 = -1
t_1 = 0
t_1 = 0
t_1 = -1
x^(1/2)+1 = 0
1*x^(1/2) = -1 // : 1
x^(1/2) = -1
( -1 < 0 i 1/2 in (0:1) ) => x naleu017Cy do O
t_1 = 0
x^(1/2)+0 = 0
x^(1/2) = 0
1*x^(1/2) = 0 // : 1
x^(1/2) = 0
x = 0
x = 0
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